geoServer发布sld样式

一个一个发布样式?

自己去geoserver中点吧。。。

批量发布样式?

将SLD样式文件上传到GeoServer

思路

编写脚本使用GeoServer REST API

1. 读文件夹下的sld文件，拿name和path
2. 读文件内容。
3. post请求 {geoserver_url}/rest/workspaces/{workspace}/styles。

完整代码

import requests
import os 

# GeoServer的URL和认证信息
geoserver_url = "http://xxx.xxx.x.xxx:9090/geoServer"
username = "admin"
password = "xxx"

# 数据存储配置
workspace = "workspace"
datastore = "datastore"


sld_directory = "F:\sld\xxx"
# 获取目录下所有SLD文件的文件名（不带扩展名）
sld_files = [os.path.splitext(f)[0] for f in os.listdir(sld_directory) if f.endswith('.sld')]

# geoserver style name：替换sld文件名咯
def rename(name):
    newName = name
    newName = newName.replace("_", "xxx_")
    return newName

# 发布样式
def publish_style(style_name, file_path):
    style_url = f"{geoserver_url}/rest/workspaces/{workspace}/styles"
    headers = {"Content-Type": "application/vnd.ogc.sld+xml; charset=utf-8"}
    with open(file_path, 'r', encoding='utf-8') as file:
        sld_content = file.read()
    params = {"name": style_name.encode('utf-8'), "workspace": workspace.encode('utf-8')}
    print(f"{style_name.encode('utf-8')}")
    response = requests.post(style_url, auth=(username, password), headers=headers, params=params, data=sld_content.encode('utf-8'))
    if response.status_code in [200, 201]:
        print(f"Style {style_name} published successfully")
    else:
        print(f"Failed to publish style {style_name}: {response.text}")

# 批量发布样式
for sld_file in sld_files:
    style_name = sld_file  # 去掉文件扩展名作为样式名
    style_name = rename(style_name)
    # print(style_name,sld_file)
    file_path = os.path.join(sld_directory, f"{sld_file}.sld")
    print(f"Publishing style: {style_name} from file: {file_path}")
    publish_style(style_name, file_path)

# 验证样式是否存在
for sld_file in sld_files:
    style_name = sld_file
    style_name = rename(style_name)
    style_url = f"{geoserver_url}/rest/workspaces/{workspace}/styles/{style_name}.json"
    response = requests.get(style_url, auth=(username, password))
    if response.status_code == 200:
        print(f"Style {style_name} details:")
        print(response.json())
    else:
        print(f"Failed to get style {style_name}: {response.text}")

tip

1. sld文件名，geoserver style name 都用英文，懒得处理乱码 = =

参考

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